It's called ball count. Individual win lose games do not apply. You get 8 balls for a win and a lesser nmbr for the lose.
What is the bca rule?
- Thread starter stickman161
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It's called ball count. Individual win lose games do not apply. You get 8 balls for a win and a lesser nmbr for the lose.
It sucks. If the best player in the league is forced to take a week off, he loses 32 balls as a result of taking the night off, which is almost impossible to get back after mid season. And if he couldn't be replaced you play with 3 players against 4. It should be just like bowling were a percentage of the missing player's avg is deducted from his average. That way the top shooter isn't knocked out, and a team can still compete with a missing shooter.
It's called BALL COUNT. Ball pocketed no matter how count.
You have over 10,000 post and still never heard of it proves how stupid this format is. We have 3 or 4 teams that take the game serious and put in practice hrs. We're the othe 20 it's a night out. We used to count wins and losses, then somebody running the league thought it would be more competitive to do BALL COUNT. That didn't work so they changed to HANDICAP. That didn't work so were back to BALL COUNT. Somehow officials can't find a way the poor players can compete with the good players. What a surprise.
Still looking for a ruling, in case it ever pops it's ugly head again.
Thanks.
Thanks.
Two things, North Dakota State team is the same way. Total balls.
My opinion on the ruling. I would think since there was a foul on the shot (break) no ball would be legally pocketed. The table is open. If the player, non-breaker, who has ball in hand takes solids, and makes a solid the breaker wins, as now the stripe is the breakers balls.
If the non-breaker, having ball in hand and open table takes stripes, he breaker would need to make it back to the table and make a solid to win.
Not saying I am correct, just how I think the rule should be. I do not know the rules of this format.
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Somebody pleas check my math. 16 games times a max of 8 balls per game is only 128 balls. So the only way to get to 128 would be to win all 16 games?
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The math is right, but they may give 3 points for the 8 (or as my league does it, the winner automatically gets 10 points even if the opponent say makes the 8 in the wrong pocket).
What I don't get is the 128 max. My league uses ball count (plus handicap) but it depends on the final total points.
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Your exactly right, but some people don't put 2@2 together.
Our league there is no rewarded for winning the game. U make 8 balls and your score is 8. This brings up another point. If you make the 8 and scratch you lose and your opponent gets 8 for the win no matter how many balls he has on the table and you only get 7 even thou you've pocketed 8 balls.
What a strange way to play 8-ball.
The answer to the question "What is the BCA(PL) rule" is that you are not playing the game according to BCAPL rules, you are playing according to your own league rules. Therefore the people you should ask are your league officers.
I run a league. Have for almost 15 years. And if I had a say as to this matter I would rule that in order to win the match you must have at least 128 points AND be at the table. Thus, when the non-breaker sinks a ball his opponent does have 128 points but he is not AT the table. Should the non-breaker miss before reaching 129, then the breaker wins.
Good point. What if you are at 126 and your opponent is at 127 and you make ball number 127 and their 128 in the same shot
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OK, but you are counting the ball made for the breaker. That being the case, since the point counts even on a scratch, did he not reach 128 while he was at the table? Assuming the OB went in before the CB, his inning didn't end until the CB dropped.
Not disagreeing with your take, just playing devil's advocate. I'm not sure what the rules would be nor if they even address this situation. But again, I have trouble with someone winning on a foul. That said however, in the more normal format of my league, in this exact situation a player coming to the table in the last game of a round could lose the round for his team simply by taking the wrong group.
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Eight ball for points is dumb imo, no offense. Having said that, your captain ought to think about what their role on the team is. If it's not to tell his teammate to elect the proper balls then what is it? You all clearly should have known it would have counted one you elected solids. You were the ones arguing, the other team was just telling you you lost. Get over it.
Our rules are you can only call a person to the table once a game. If your standing at the table with ball in hand needing 2 more balls counting the one made on the break, you should lose if you take solids.
I could care less I'm in it for fun not blood and guts.
OK, but you are counting the ball made for the breaker. That being the case, since the point counts even on a scratch, did he not reach 128 while he was at the table? Assuming the OB went in before the CB, his inning didn't end until the CB dropped.
Not disagreeing with your take, just playing devil's advocate. I'm not sure what the rules would be nor if they even address this situation. But again, I have trouble with someone winning on a foul. That said however, in the more normal format of my league, in this exact situation a player coming to the table in the last game of a round could lose the round for his team simply by taking the wrong group.
That's my understanding too. Thanks