Throw
- Thread starter alstl
- Start date
The lesser the extent of throw (at any one given contact point). This is according to Dr. Dave's FAQs page.
EDIT: Nevermind, I'm not going to get into it. 
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mods, cmon....delete this poll/thread.
you cant create a poll where there question is governed by the laws of physics.
you cant create a poll where there question is governed by the laws of physics.
I voted
What's one foot North of the North Pole?
Up or down?
Here's a plot of measurements I did in about 1984.
So the answer is that for some cut angles, the throw angle is the same for all speeds while for thinner cut angles, the throw angle decreases with more force.
So the answer is that for some cut angles, the throw angle is the same for all speeds while for thinner cut angles, the throw angle decreases with more force.
Here's a plot of measurements I did in about 1984.
So the answer is that for some cut angles, the throw angle is the same for all speeds while for thinner cut angles, the throw angle decreases with more force.
Thanks, I was hoping you would reply. It's something I've wondered about for awhile and I just was browsing through Byrne's Advanced Technique in Pool and Billiards and your name appears in the section on throw, page 24.
I imagine cleanliness of the balls is also a factor.
Force the Angle
An example, your cutting an object ball lets say at a 40 degree angle. If the contact point on the object ball is unchanged, then as you strike the object ball(exact same contact point) with more cue ball speed the object ball will overcut ever so slightly more as you increase speed, one also has to remember when using draw you adding speed of cue ball rotation combined with actual cue ball forward speed thus causing more overcut. There's a term in pool called forcing the angle, in essence with forward and rotational increase of cue ball speed, your accomplishing this terminology.
An example, your cutting an object ball lets say at a 40 degree angle. If the contact point on the object ball is unchanged, then as you strike the object ball(exact same contact point) with more cue ball speed the object ball will overcut ever so slightly more as you increase speed, one also has to remember when using draw you adding speed of cue ball rotation combined with actual cue ball forward speed thus causing more overcut. There's a term in pool called forcing the angle, in essence with forward and rotational increase of cue ball speed, your accomplishing this terminology.
I think that it depends on your CTE pivot.
Now, if you don't mind, I'm going to go get some popcorn to sit back and enjoy the show. :wink::grin:
Orville Redenbacher used CTE but he denied it in public.
I've also done lot of analysis and experiments related to throw effects. My results are consistent with Bob's data.Here's a plot of measurements I did in about 1984.
So the answer is that for some cut angles, the throw angle is the same for all speeds while for thinner cut angles, the throw angle decreases with more force.
As Bob points out, speed affects throw only for certain cut angles. FYI, the following video has some good examples of throw speed effects:
Throw varies with all sorts of things in addition to speed. For a complete list, along with supporting articles and videos, see items 15-25 in the list available here:
BTW, this is an excellent "trick question" poll. Everybody who answered is wrong, depending on the cut angle.
Regards,
Dave
It wasn't intended to be a trick question but I'm glad I got the correct answer from a couple of guys whose opinion I respect.
I was actually looking in one of Byrne's books for a system to calculate the plus two system off a ball. Turns out the system I was using is what he recommends, which is to geusstimate the angle and contact point of the cue ball on the rail and they apply the system. Then I saw his section about throw and decided to make this thread.
Thanks for the reply and the information.
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