There are several simple demonstrations of throw, and if you know the physics involved, it's easy to see why throw must happen given a few simple observations. Here is the demo I like. With both the cue ball and object ball exactly one ball diameter off the cushion, it is possible to make the object ball hit the GB (gauge ball) and get the cue ball to move towards the cushion, ending less than a ball from the cushion. (The question that the diagram was designed for was to find out how far apart the balls could be and still get this result -- closer is easier.)...
It still seems odd, but I couldn't prove him wrong.
There are several simple demonstrations of throw, and if you know the physics involved, it's easy to see why throw must happen given a few simple observations. Here is the demo I like. With both the cue ball and object ball exactly one ball diameter off the cushion, it is possible to make the object ball hit the GB (gauge ball) and get the cue ball to move towards the cushion, ending less than a ball from the cushion. (The question that the diagram was designed for was to find out how far apart the balls could be and still get this result -- closer is easier.)
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Not exactly. Most of the time when people use the word "skid" in this context, it means a very, very extreme kind of throw due to the contact surface of the collision being much more sticky than it usually is. This seems to usually be from a chalk spot at the contact point. When you get a skid -- which is also called "cling" in the US, "kick" in the UK and other snooker-playing countries, and "bad contact" by carom players speaking in English -- the object ball may throw by several times its usual amount of throw.... Isn't a ball that skids just a ball thrown by the cueball?
My experience is that I can throw a ball with pretty much any diameter shaft, but with a larger shaft it is harder to judge the squirt. That difficulty of controlling squirt for a thick shaft may mask the effect of throw.The amount of spin induced throw is also very cue dependent. With a 13+mm shaft it's close to impossible to throw a ball with spin.
i learned from some esteemed players and mentors in my snooker days, it is possible to transfer a small amount of spin to the o.b. that was 30 years ago.
since then i have demonstrated this fact using two striped balls and a pocket speed hit, to many non believers and opponents. cloth and ball condition have a great influence over this phenomenon. simply set the 2 balls up with the stripe vertical. 1 ball is the c.b., the other the o.b.
enjoy the can of worms!
p.s. one of the "esteemed", became world snooker champion in the 80's.
... Ron claims it is impossible to throw an object ball. ...
My experience is that I can throw a ball with pretty much any diameter shaft, but with a larger shaft it is harder to judge the squirt. That difficulty of controlling squirt for a thick shaft may mask the effect of throw.
I don't know if you mean it this way, but the transferred spin doesn't change the path of the object ball. The OB's path is changed only by (and during) contact with the CB; the transferred spin is a side effect.cleary:
Spin is transferred and it changes the path of the object ball.
A ball in good condition can throw an inch per diamond. That's a few inches for an average shot and half a foot for a long shot.So maybe the truth of the matter is that the throw (especially with clean balls) is much less pronounced as many may presume it to be.
There is about the same squirt at all speeds for a given off-center hit. What changes a lot with speed is the amount of swerve you have and to a smaller extent the amount of throw.Whenever I try to use gearing english with a large shaft I'll undercut certain shots as if I used just centerball. Doesn't the squirt happen at higher speeds?